## Smallest multiple

First read the problem description.

We just need to find the lcm.

```
from math import gcd
def lcm(a, b):
return a*b // gcd(a, b)
= 1
l for n in range(1,20+1):
= lcm(l, n)
l l
```

`232792560`

### Comments

Source code of the solution(s):