{
 "cells": [
  {
   "cell_type": "code",
   "execution_count": 4,
   "metadata": {},
   "outputs": [],
   "source": [
    "digits = \"\"\"\n",
    "73167176531330624919225119674426574742355349194934\n",
    "96983520312774506326239578318016984801869478851843\n",
    "85861560789112949495459501737958331952853208805511\n",
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    "17866458359124566529476545682848912883142607690042\n",
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    "71636269561882670428252483600823257530420752963450\n",
    "\"\"\".replace('\\n', '')\n",
    "\n",
    "maximum = 0\n",
    "for i in range(0, len(digits)-13 + 1):\n",
    "    product = 1\n",
    "    for d in digits[i:i+13]:\n",
    "        product *= int(d)\n",
    "    maximum = max(product, maximum)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": []
  }
 ],
 "metadata": {
  "kernelspec": {
   "display_name": "Python 3",
   "language": "python",
   "name": "python3"
  },
  "language_info": {
   "codemirror_mode": {
    "name": "ipython",
    "version": 3
   },
   "file_extension": ".py",
   "mimetype": "text/x-python",
   "name": "python",
   "nbconvert_exporter": "python",
   "pygments_lexer": "ipython3",
   "version": "3.7.4"
  },
  "title": "Largest product in a series"
 },
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}